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last edited 6 years ago by test int |
Edit detail for SandBoxReduce revision 31 of 36
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Editor: crashcut
Time: 2008/01/31 07:57:43 GMT-8 |
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added:
From crashcut Thu Jan 31 07:57:39 -0800 2008
From: crashcut
Date: Thu, 31 Jan 2008 07:57:39 -0800
Subject:
Message-ID: <20080131075739-0800@axiom-wiki.newsynthesis.org>
\begin{reduce}
solve({y=-1/l*(1-(l*x+(-3*l^2-l+8)^(1/2)/4-0.5*l)^2)^(1/2) -(-3*l^2-l+8)^(1/2)/(4*l)+2*l}, {y});
\end{reduce}
Try Reduce calculations here. For example:
\begin{reduce}
solve({z=x*a+2},{z,x});
int(sqrt(1-sin(x)*cos(x)),x);
\end{reduce}
1: solve({z=x*a+2},{z,x}); | reduce |
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int(sqrt(1-sin(x)*cos(x)),x); | reduce |
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example from my daughter's college calc --pbwagner, Mon, 10 Sep 2007 12:58:25 -0500 reply
int(log(log(x)),x); | reduce |
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axiom
integrate(log(log(x)),x)
 | (1) |
Type: Union(Expression Integer,...)
solve({y=-1/l*(1-(l*x+(-3*l^2-l+8)^(1/2)/4-0.5*l)^2)^(1/2) -(-3*l^2-l+8)^(1/2)/(4*l)+2*l}, {y}); | reduce |
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