Edit detail for SandBoxReduce revision 22 of 36

added:

From crashcut Thu Jan 31 02:40:56 -0800 2008
From: crashcut
Date: Thu, 31 Jan 2008 02:40:56 -0800
Subject: 
Message-ID: <20080131024056-0800@axiom-wiki.newsynthesis.org>

solve({y=-1/l*(1-(l*x+c1)^2)^(1/2)+c2, c1=((-3*l^2-l+8)^(1/2)/4-l, c2=-3((-3*l^2-l+8)^(1/2)+7*l)/12*l}, {y});

Try Reduce calculations here. For example:

  \begin{reduce}
  solve({z=x*a+2},{z,x});
  int(sqrt(1-sin(x)*cos(x)),x);
  \end{reduce}

solve({z=x*a+2},{z,x});

reduce

int(sqrt(1-sin(x)*cos(x)),x);

reduce

example from my daughter's college calc --pbwagner, Mon, 10 Sep 2007 12:58:25 -0500 reply

int(log(log(x)),x);

reduce

axiom
integrate(log(log(x)),x)

(1)

Type: Union(Expression Integer,...)

... --crashcut, Wed, 30 Jan 2008 10:28:27 -0800 reply

solve({c=-1/m*(1-(m*a+c1)^2)^(1/2)+c2, b=-1/m*(1-c1^2)^(1/2)+c2}, {c1,c2});

reduce

... --crashcut, Thu, 31 Jan 2008 02:40:56 -0800 reply

solve({y=-1/l(1-(lx+c1)^2)^(1/2)+c2, c1=((-3l^2-l+8)^(1/2)/4-l, c2=-3((-3l^2-l+8)^(1/2)+7l)/12l}, {y});