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SandBoxFriCAS

last edited 11 months ago by test1

Edit detail for SandBoxFriCAS revision 13 of 62

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Editor: panacea Time: 2014/11/21 18:25:05 GMT+0
Note:

added:

From panacea Fri Nov 21 18:25:05 +0000 2014
From: panacea
Date: Fri, 21 Nov 2014 18:25:05 +0000
Subject: 
Message-ID: <20141121182505+0000@axiom-wiki.newsynthesis.org>

guessRec([1,1,0,1,- 1,2,- 1,5,- 4,29,- 13,854,- 685])

This page is set to execute \begin{axiom}... \end{axiom} commands using FriCAS?:

fricas

)version

Value = "FriCAS 1.2.3 compiled at Sat May  3 02:17:51 UTC 2014"

Any comments added here with use this version of FriCAS?.

... --meliusja, Tue, 08 Apr 2008 10:38:33 -0700 reply

fricas

solve(s=v*t+a*t^2/2,t)

$\label{eq1}\left[{{{2 \ t \ v}+{a \ {{t}^{2}}}-{2 \ s}}= 0}\right]$

(1)

Type: List(Equation(Fraction(Polynomial(Integer))))

... --meliusja, Tue, 08 Apr 2008 10:39:28 -0700 reply

fricas

radicalSolve(s=v*t+a*t^2/2,t)

$\label{eq2}\left[{t ={{-{\sqrt{{4 \ {{v}^{2}}}+{8 \ a \ s}}}-{2 \ v}}\over{2 \ a}}}, \:{t ={{{\sqrt{{4 \ {{v}^{2}}}+{8 \ a \ s}}}-{2 \ v}}\over{2 \ a}}}\right]$

(2)

Type: List(Equation(Expression(Integer)))

... --meliusja, Tue, 08 Apr 2008 10:40:28 -0700 reply

fricas

solve(v*t+a*t^2/2-s=0,t)

$\label{eq3}\left[{{{2 \ t \ v}+{a \ {{t}^{2}}}-{2 \ s}}= 0}\right]$

(3)

Type: List(Equation(Fraction(Polynomial(Integer))))

... --meliusja, Tue, 08 Apr 2008 10:41:13 -0700 reply

fricas

solve(v*t+a*t/2-s=0,t)

$\label{eq4}\left[{t ={{2 \ s}\over{{2 \ v}+ a}}}\right]$

(4)

Type: List(Equation(Fraction(Polynomial(Integer))))

... --meliusja, Tue, 08 Apr 2008 10:42:37 -0700 reply

fricas

solve(v*t+a*t^2/2-s=0,t)

$\label{eq5}\left[{{{2 \ t \ v}+{a \ {{t}^{2}}}-{2 \ s}}= 0}\right]$

(5)

Type: List(Equation(Fraction(Polynomial(Integer))))

fricas

radicalSolve(p^3 - p + 1/10=0,p)

$\label{eq6}\begin{array}{@{}l} \displaystyle \left[{p ={{{{\left(-{3 \ {\sqrt{- 3}}}+ 3 \right)}\ {{\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{373}}}}\over{{60}\ {\sqrt{3}}}}}^{2}}}- 2}\over{{\left({3 \ {\sqrt{- 3}}}+ 3 \right)}\ {\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{373}}}}\over{{60}\ {\sqrt{3}}}}}}}}, \: \right. \ \ \displaystyle \left.{p ={{{{\left(-{3 \ {\sqrt{- 3}}}- 3 \right)}\ {{\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{373}}}}\over{{60}\ {\sqrt{3}}}}}^{2}}}+ 2}\over{{\left({3 \ {\sqrt{- 3}}}- 3 \right)}\ {\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{373}}}}\over{{60}\ {\sqrt{3}}}}}}}}, \: \right. \ \ \displaystyle \left.{p ={{{3 \ {{\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{37 3}}}}\over{{60}\ {\sqrt{3}}}}}^{2}}}+ 1}\over{3 \ {\root{3}\of{{-{3 \ {\sqrt{3}}}+{\sqrt{-{373}}}}\over{{60}\ {\sqrt{3}}}}}}}}\right]$

(6)

Type: List(Equation(Expression(Integer)))

fricas

R1 ==> Record(foo1: String, remLexs: List Integer)

Type: Void

fricas

R2 ==> Record(foo2: String, remLexs: List Integer)

Type: Void

fricas

r1: R1 := ["a", [1,2,3]]

$\label{eq7}\left[{foo 1 = \mbox{\tt "a"}}, \:{remLexs ={\left[ 1, \: 2, \: 3 \right]}}\right]$

(7)

Type: Record(foo1: String,remLexs: List(Integer))

fricas

r2: R2 := ["b", [5]]

$\label{eq8}\left[{foo 2 = \mbox{\tt "b"}}, \:{remLexs ={\left[ 5 \right]}}\right]$

(8)

Type: Record(foo2: String,remLexs: List(Integer))

fricas

r1.remLexs

$\label{eq9}\left[ 1, \: 2, \: 3 \right]$

(9)

Type: List(Integer)

fricas

r2.remLexs

$\label{eq10}\left[ 5 \right]$

(10)

Type: List(Integer)

... --test1, Tue, 26 Mar 2013 18:40:29 +0000 reply