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Editor: kratt6
Time: 2009/01/13 16:15:23 GMT-8
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Note:
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added:
Hm, it seems unreproducible here. It is reproducible on my machine, though...
changed:
-count(true, [(product(product(f j, j=1..i), i=1..n)=product(product(f k, k=1..j), j=1..n))@Boolean for m in 1..100])
f := operator 'f
count(true, [(product(product(f j, j=1..i), i=1..n)=product(product(f k, k=1..j), j=1..n))@Boolean for m in 1..200])
Hm, it seems unreproducible here. It is reproducible on my machine, though...
axiom
f := operator 'f
axiom
count(true, [(product(product(f j, j=1..i), i=1..n)=product(product(f k, k=1..j), j=1..n))@Boolean for m in 1..200])