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Editor: hemmecke
Time: 2008/08/15 11:09:22 GMT-7 |
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Note: |
changed: - Some demo involving the algebraic number $\sqrt{3}$. \begin{axiom} t1 := (sqrt(3)-3)*(sqrt(3)+1)/6 tt1 := -1/sqrt(3) t2 := sqrt(3)/6 t1+t2 tt1+t2 \end{axiom} Note that in PanAxiom the above are not generic expressions but of type 'AlgebraicNumber'.
Some demo involving the algebraic number .
t1 := (sqrt(3)-3)*(sqrt(3)+1)/6
![]() | (1) |
tt1 := -1/sqrt(3)
![]() | (2) |
t2 := sqrt(3)/6
![]() | (3) |
t1+t2
![]() | (4) |
tt1+t2
![]() | (5) |
Note that in PanAxiom? the above are not generic expressions but of
type AlgebraicNumber
.