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last edited 11 years ago by test1 |
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last edited 11 years ago by test1 |
![\label{eq2}\begin{array}{@{}l}
\displaystyle
\left[{x ={2 \ {\arctan \left({\%x 0}\right)}}}, \:{x ={2 \ {\arctan \left({\%x 1}\right)}}}, \: \right.
\
\
\displaystyle
\left.{
\begin{array}{@{}l}
\displaystyle
x ={2 \ {\arctan{\left({\frac{{\sqrt{-{{27}\ {{\%x 1}^{2}}}+{{\left(-{{18}\ \%x 0}-{30}\right)}\ \%x 1}-{{27}\ {{\%x 0}^{2}}}-{{3
0}\ \%x 0}+{37}}}-{3 \ \%x 1}-{3 \ \%x 0}- 5}{6}}\right)}}}](images/8989084854634294478-16.0px.png "\label{eq2}\begin{array}{@{}l}
\displaystyle
\left[{x ={2 \ {\arctan \left({\%x 0}\right)}}}, \:{x ={2 \ {\arctan \left({\%x 1}\right)}}}, \: \right.
\
\
\displaystyle
\left.{
\begin{array}{@{}l}
\displaystyle
x ={2 \ {\arctan{\left({\frac{{\sqrt{-{{27}\ {{\%x 1}^{2}}}+{{\left(-{{18}\ \%x 0}-{30}\right)}\ \%x 1}-{{27}\ {{\%x 0}^{2}}}-{{3
0}\ \%x 0}+{37}}}-{3 \ \%x 1}-{3 \ \%x 0}- 5}{6}}\right)}}}")
![\label{eq3}\begin{array}{@{}l}
\displaystyle
\left[{\frac{\log \left({\frac{{{\left({{x}^{2}}- a \right)}\ {\sqrt{- a}}}+{2 \ a \ x}}{{{x}^{2}}+ a}}\right)}{2 \ {\sqrt{- a}}}}, \: \right.
\
\
\displaystyle
\left.{\frac{\arctan \left({\frac{x \ {\sqrt{a}}}{a}}\right)}{\sqrt{a}}}\right]](images/929731673531133874-16.0px.png "\label{eq3}\begin{array}{@{}l}
\displaystyle
\left[{\frac{\log \left({\frac{{{\left({{x}^{2}}- a \right)}\ {\sqrt{- a}}}+{2 \ a \ x}}{{{x}^{2}}+ a}}\right)}{2 \ {\sqrt{- a}}}}, \: \right.
\
\
\displaystyle
\left.{\frac{\arctan \left({\frac{x \ {\sqrt{a}}}{a}}\right)}{\sqrt{a}}}\right]")