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#15 integrate(1/(1+z^4), z=0..1) :: Complex Float ←	↑	→ #151 Environment variable AXIOM

#150 To create a function from an expresion

Edit detail for #150 To create a function from an expresion revision 1 of 1

	1
Editor: Time: 2007/11/17 21:58:32 GMT-8
Note:

changed:
-
I don't now how ...
If I enter:

\begin{axiom}
expr:= 3*x
f(x) == expr
f(5)
\end{axiom}

I get an output of $3x$; I would like an output of  15.
Is there a way to do it right? 



From MartinRubey Thu Apr 28 11:49:58 -0500 2005
From: Martin Rubey
Date: Thu, 28 Apr 2005 11:49:58 -0500
Subject: [#150 To create a function from an expresion]	(new) 
Message-ID: <17009.5116.793917.607691@seam101.local>
In-Reply-To: <20050428111446-0500@page.axiom-developer.org>

\begin{axiom}
)clear all
expr := 3*x
function(expr, f, x)
f(5)
\end{axiom}

Martin


From loli Thu Apr 28 21:53:36 -0500 2005
From: loli
Date: Thu, 28 Apr 2005 21:53:36 -0500
Subject: property change
Message-ID: <20050428215336-0500@page.axiom-developer.org>

Status: open => closed

I don't now how ... If I enter:

fricas

(1) -> expr:= 3*x

$\label{eq1}3 \ x$

(1)

Type: Polynomial(Integer)

fricas

f(x) == expr

Type: Void

fricas

f(5)

fricas

Compiling function f with type PositiveInteger -> Polynomial(Integer
      )

$\label{eq2}3 \ x$

(2)

Type: Polynomial(Integer)

I get an output of ; I would like an output of 15. Is there a way to do it right?

#150 To create a function from an expresion (new) --Martin Rubey, Thu, 28 Apr 2005 11:49:58 -0500 reply

fricas

)clear all

   All user variables and function definitions have been cleared.
expr := 3*x

$\label{eq3}3 \ x$

(3)

Type: Polynomial(Integer)

fricas

function(expr, f, x)

$\label{eq4}f$

(4)

Type: Symbol

fricas

f(5)

fricas

Compiling function f with type PositiveInteger -> PositiveInteger

$\label{eq5}15$

(5)

Type: PositiveInteger?

Martin

property change --loli, Thu, 28 Apr 2005 21:53:36 -0500 reply

Status: open => closed