MathAction SandBoxBugFactor

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fricas

(1) -> t:=(4*x^3+2*y^2+1)*(12*x^5-x^3*y+12)*(x+1)*(y^2+3)*(x^2-1)

$\label{eq1}\begin{array}{@{}l} \displaystyle {{\left(-{2 \ {{x}^{6}}}-{2 \ {{x}^{5}}}+{2 \ {{x}^{4}}}+{2 \ {{x}^{3}}}\right)}\ {{y}^{5}}}+ \ \ \displaystyle {{\left({ \begin{array}{@{}l} \displaystyle {{24}\ {{x}^{8}}}+{{24}\ {{x}^{7}}}-{{24}\ {{x}^{6}}}-{{24}\ {{x}^{5}}}+{{24}\ {{x}^{3}}}+{{24}\ {{x}^{2}}}- \ \ \displaystyle {{24}\ x}-{24}$

(1)

Type: Polynomial(Integer)

fricas

factor t

$\label{eq2}\begin{array}{@{}l} \displaystyle -{ \begin{array}{@{}l} \displaystyle {\left(x - 1 \right)}\ {{\left(x + 1 \right)}^{2}}\ {\left({{{x}^{3}}\ y}-{{12}\ {{x}^{5}}}-{12}\right)}\ {\left({{y}^{2}}+ 3 \right)}\ \cdot \ \ \displaystyle {\left({2 \ {{y}^{2}}}+{4 \ {{x}^{3}}}+ 1 \right)}$

(2)

Type: Factored(Polynomial(Integer))

Subject: Be Bold !!

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