I don't now how ... If I enter: axiom expr:= 3*x
Type: Polynomial(Integer)
axiom f(x) == expr Type: Void
axiom f(5) axiom Compiling function f with type PositiveInteger -> Polynomial(Integer )
Type: Polynomial(Integer)
I get an output of ; I would like an output of 15. Is there a way to do it right? #150 To create a function from an expresion (new) --Martin Rubey, Thu, 28 Apr 2005 11:49:58 -0500 reply axiom )clear all
Type: Polynomial(Integer)
axiom function(expr,
Type: Symbol
axiom f(5) axiom Compiling function f with type PositiveInteger -> PositiveInteger
Type: PositiveInteger?
Martin Status: open => closed |